Random Resource Query using PyVISA

The function uses the PyVISA library to query a random resource of a specified type, such as GPIB or TCPIP. It attempts to open a randomly selected resource and returns it when it reaches the maximum number of attempts or successfully opens a resource. If it cannot open the resource, it returns None.

Technology Stack : PyVISA

Code Type : The type of code

Code Difficulty : Intermediate

                
                    
import random

def random_resource_query(resource_type, max_attempts=5):
    """
    Query a random resource of a given type using PyVISA.

    Args:
        resource_type (str): The type of resource to query (e.g., 'GPIB', 'TCPIP').
        max_attempts (int): The maximum number of attempts to find a resource.

    Returns:
        object: A PyVISA resource object if found, otherwise None.
    """
    from pyvisa import ResourceManager

    rm = ResourceManager()
    attempts = 0
    while attempts < max_attempts:
        resource_name = rm.list_resources(resource_type=resource_type)[random.randint(0, len(rm.list_resources(resource_type=resource_type))-1)]
        try:
            resource = rm.open_resource(resource_name)
            return resource
        except Exception as e:
            attempts += 1
            print(f"Attempt {attempts}/{max_attempts}: {e}")

    return None