Random Resource Selection with Type Matching

This function randomly selects a resource from the PyVISA library and checks if its type matches the provided resource type. If it matches, it returns the resource; otherwise, it returns None.

Technology Stack : PyVISA

Code Type : The type of code

Code Difficulty : Intermediate

                
                    
import random
from pyvisa import resources

def random_resource_search(resource_type):
    resources_list = resources.list_resources()
    selected_resource = random.choice(resources_list)
    if resource_type in selected_resource:
        return selected_resource
    else:
        return None