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This function is used to pack multiple iterable objects into tuples, if the elements in an iterable object are insufficient, it uses fillvalue to fill.
Technology Stack : itertools
Code Type : Function
Code Difficulty : Intermediate
def zip_longest(*args, fillvalue=0):
"""
从a~z的顺序中,使用了内置的`zip_longest`函数,用于将可迭代对象打包成元组,如果某个可迭代对象中缺少元素,则使用fillvalue填充。
"""
from itertools import zip_longest
def next_item():
for item in args:
if len(item) > 0:
yield item[0]
item.pop(0)
while True:
try:
yield tuple(next_item())
except IndexError:
break