Iterating Through Uneven Length Iterables with FillValue

The function aggregates elements from each of the provided iterable objects. If the iterables have different lengths, missing values are filled with a specified value.

Technology Stack : itertools

Code Type : Function

Code Difficulty : Intermediate

                
                    
def zip_longest(*iterables, fillvalue=None):
    "Make an iterator that aggregates elements from each of the iterables.
    If the iterables are of uneven length, missing values are filled-in with fillvalue.
    Parameters
    ----------
    iterables : sequence or iterator
        An iterable series of iterables.
    fillvalue : optional
        The value to use for missing values if the iterables are of uneven length.
    Examples
    --------
    >>> list(zip_longest([1, 2, 3], 'abc', fillvalue=-1))
    [(1, 'a', -1), (2, 'b', -1), (3, 'c', -1)]
    >>> list(zip_longest([1, 2, 3, 4], 'abc', fillvalue='x'))
    [(1, 'a', None), (2, 'b', None), (3, 'c', None), (4, 'd', 'x')]
    >>> list(zip_longest('abc', 'def', fillvalue=0))
    [('a', 'd', 0), ('b', 'e', 0), ('c', 'f', 0)]
    """
    from itertools import zip_longest as _zip_longest
    return _zip_longest(*iterables, fillvalue=fillvalue)