Iterative Zip with Fillvalue

This function creates a new iterator from an arbitrary number of iterable objects. If any iterable is exhausted, it continues iteration with a specified fill value.

Technology Stack : Iterator, generator, tuple unpacking

Code Type : Function

Code Difficulty : Intermediate

                
                    
def zip_longest(*args, fillvalue=0):
    iters = [iter(args[i]) for i in range(len(args))]
    while True:
        result = []
        for i, it in enumerate(iters):
            try:
                result.append(next(it))
            except StopIteration:
                iters[i] = iter([fillvalue])
                result.append(next(iters[i]))
        yield result