You can download this code by clicking the button below.
This code is now available for download.
Converts two decimal numbers to Roman numerals and calculates their sum.
Technology Stack : Built-in data structures, sorting
Code Type : Function
Code Difficulty : Intermediate
def abacuses_sum(num1, num2):
"""
计算两个十进制数字的罗马数字和。
:param num1: 第一个十进制数字
:param num2: 第二个十进制数字
:return: 两个十进制数字对应的罗马数字之和
"""
roman_numerals = {
1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L',
90: 'XC', 100: 'C', 400: 'CD', 500: 'D', 900: 'CM', 1000: 'M'
}
def int_to_roman(num):
result = ''
for value in sorted(roman_numerals.keys(), reverse=True):
while num >= value:
result += roman_numerals[value]
num -= value
return result
return int_to_roman(num1) + int_to_roman(num2)