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This function implements a simple abacus algorithm to calculate the sum of two integers. It converts each number into an abacus representation, then performs the addition digit by digit, and handles carry.
Technology Stack : Built-in functions (map, range, list, int, ''.join)
Code Type : Function
Code Difficulty : Intermediate
def abacus_sum(a, b):
"""
使用算盘算法计算两个整数的和。
"""
# 初始化算盘
abacus = [0] * 10
# 将数字a和b转换为算盘表示
for digit in a:
abacus[digit] += 1
for digit in b:
abacus[digit] += 1
# 计算和,并处理进位
result = []
carry = 0
for i in range(9, -1, -1):
total = abacus[i] + carry
result.append(total % 10)
carry = total // 10
# 如果最高位有进位,则添加到结果中
if carry > 0:
result.append(carry)
# 将结果转换为整数
return int(''.join(map(str, result[::-1])))