Abacus Algorithm for Integer Addition

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Code introduction


This function implements a simple abacus algorithm to calculate the sum of two integers. It converts each number into an abacus representation, then performs the addition digit by digit, and handles carry.


Technology Stack : Built-in functions (map, range, list, int, ''.join)

Code Type : Function

Code Difficulty : Intermediate


                
                    
def abacus_sum(a, b):
    """
    使用算盘算法计算两个整数的和。
    """
    # 初始化算盘
    abacus = [0] * 10
    # 将数字a和b转换为算盘表示
    for digit in a:
        abacus[digit] += 1
    for digit in b:
        abacus[digit] += 1
    # 计算和,并处理进位
    result = []
    carry = 0
    for i in range(9, -1, -1):
        total = abacus[i] + carry
        result.append(total % 10)
        carry = total // 10
    # 如果最高位有进位,则添加到结果中
    if carry > 0:
        result.append(carry)
    # 将结果转换为整数
    return int(''.join(map(str, result[::-1])))