Creating a Zip Object from Multiple Iterables

This function accepts an arbitrary number of iterable objects as arguments and returns a zip object that aggregates elements from each of the iterables.

Technology Stack : Built-in function zip

Code Type : Function

Code Difficulty :

                
                    
def zip(*args):
    """
    Create a zip object that aggregates elements from multiple iterable objects.

    Parameters:
    *args: An arbitrary number of iterable objects.

    Returns:
    A zip object.

    Example:
    >>> list(zip([1, 2, 3], 'abc'))
    [(1, 'a'), (2, 'b'), (3, 'c')]
    """
    return zip(*args)