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This function uses `itertools.zip_longest` to fill shorter input sequences until they reach the same length as the longest sequence. It uses `collections.deque` to efficiently handle sequences, and utilizes built-in functions such as `operator.itemgetter`, `functools.reduce`, `bisect.bisect_left`, and `math.ceil` to calculate and manipulate data.
Technology Stack : itertools, collections, operator, functools, bisect, math
Code Type : Function
Code Difficulty : Intermediate
def zip_longest(*args, fillvalue=None):
from itertools import zip_longest
from collections import deque
from operator import itemgetter
from functools import reduce
from bisect import bisect_left
from math import ceil
def align_deques(deques):
lengths = [len(d) for d in deques]
max_length = max(lengths)
return [deque.extend([fillvalue] * (max_length - len(d))) for d in deques]
def split_deques(deques):
for d in deques:
while d and d[0] is fillvalue:
d.popleft()
return deques
# Ensure all inputs are deques
deques = [deque(args[i]) for i in range(len(args))]
# Align all deques to the length of the longest
deques = align_deques(deques)
# Get the lengths of all deques
lengths = [len(d) for d in deques]
# Calculate the total length of the output
total_length = sum(lengths)
# Calculate the maximum number of elements per chunk
chunk_size = ceil(total_length / len(deques))
# Initialize the output list
output = []
# Iterate over chunks of the total length
for i in range(0, total_length, chunk_size):
# Get the chunk from each deque
chunk = [d[i:i + chunk_size] for d in deques]
# Split off the fillvalue chunks and re-align
chunk = split_deques(chunk)
# Convert the chunk to a list and append to output
output.append(list(chunk))
return output