Code introduction
This function creates an iterator that aggregates elements from each of the provided iterables. The iterator returns a tuple containing one element from each of the iterables. If the iterables are of uneven length, missing values are filled-in with fillvalue. Elements are taken from the iterables in a cyclic order, which means that the iterator does not reset the starting position of each iterable every time it returns a tuple. Instead, it continues from where it left off, potentially reusing values from the beginning of an iterable if the end is reached first.
Technology Stack : itertools
Code Type : Iterator
Code Difficulty : Intermediate
def zip_longest(*args, fillvalue=()):
"""Create an iterator that aggregates elements from each of the iterables. The iterator returns a tuple containing one element from each of the iterables. If the iterables are of uneven length, missing values are filled-in with fillvalue. Elements are taken from the iterables in a cyclic order. This means that the iterator does not reset the starting position of each iterable every time it returns a tuple. Instead, it continues from where it left off, potentially reusing values from the beginning of an iterable if the end is reached first.
Args:
*args: An arbitrary number of iterables.
fillvalue: The value to use for missing values if the iterables are of uneven length.
Returns:
An iterator that aggregates elements from the provided iterables.
"""
from itertools import zip_longest
return zip_longest(*args, fillvalue=())