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Compare two strings in dictionary order and return the differences between them.
Technology Stack : sorted, zip, list
Code Type : Function
Code Difficulty : Intermediate
def aordiff(arg1, arg2):
"""
对两个字符串进行字典序比较,并返回它们之间的差异。
"""
# 使用内置的sorted函数对两个字符串进行排序
sorted_arg1 = sorted(arg1)
sorted_arg2 = sorted(arg2)
# 使用内置的zip函数将两个排序后的字符串组合起来
zipped_args = zip(sorted_arg1, sorted_arg2)
# 使用内置的list函数创建一个列表来存储差异
differences = list(zipped_args)
# 如果两个字符串长度不同,添加剩余的字符
if len(sorted_arg1) > len(sorted_arg2):
differences.extend(sorted_arg1[len(sorted_arg2):])
elif len(sorted_arg2) > len(sorted_arg1):
differences.extend(sorted_arg2[len(sorted_arg1):])
# 返回差异列表
return differences